Integrand size = 22, antiderivative size = 255 \[ \int \frac {x^{3/2} \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {2 (A b-a B) \sqrt {x}}{b^2}+\frac {2 B x^{5/2}}{5 b}+\frac {\sqrt [4]{a} (A b-a B) \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{9/4}}-\frac {\sqrt [4]{a} (A b-a B) \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{9/4}}+\frac {\sqrt [4]{a} (A b-a B) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{9/4}}-\frac {\sqrt [4]{a} (A b-a B) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{9/4}} \]
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Time = 0.15 (sec) , antiderivative size = 255, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.409, Rules used = {470, 327, 335, 217, 1179, 642, 1176, 631, 210} \[ \int \frac {x^{3/2} \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {\sqrt [4]{a} (A b-a B) \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{9/4}}-\frac {\sqrt [4]{a} (A b-a B) \arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}+1\right )}{\sqrt {2} b^{9/4}}+\frac {\sqrt [4]{a} (A b-a B) \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{2 \sqrt {2} b^{9/4}}-\frac {\sqrt [4]{a} (A b-a B) \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{2 \sqrt {2} b^{9/4}}+\frac {2 \sqrt {x} (A b-a B)}{b^2}+\frac {2 B x^{5/2}}{5 b} \]
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Rule 210
Rule 217
Rule 327
Rule 335
Rule 470
Rule 631
Rule 642
Rule 1176
Rule 1179
Rubi steps \begin{align*} \text {integral}& = \frac {2 B x^{5/2}}{5 b}-\frac {\left (2 \left (-\frac {5 A b}{2}+\frac {5 a B}{2}\right )\right ) \int \frac {x^{3/2}}{a+b x^2} \, dx}{5 b} \\ & = \frac {2 (A b-a B) \sqrt {x}}{b^2}+\frac {2 B x^{5/2}}{5 b}-\frac {(a (A b-a B)) \int \frac {1}{\sqrt {x} \left (a+b x^2\right )} \, dx}{b^2} \\ & = \frac {2 (A b-a B) \sqrt {x}}{b^2}+\frac {2 B x^{5/2}}{5 b}-\frac {(2 a (A b-a B)) \text {Subst}\left (\int \frac {1}{a+b x^4} \, dx,x,\sqrt {x}\right )}{b^2} \\ & = \frac {2 (A b-a B) \sqrt {x}}{b^2}+\frac {2 B x^{5/2}}{5 b}-\frac {\left (\sqrt {a} (A b-a B)\right ) \text {Subst}\left (\int \frac {\sqrt {a}-\sqrt {b} x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{b^2}-\frac {\left (\sqrt {a} (A b-a B)\right ) \text {Subst}\left (\int \frac {\sqrt {a}+\sqrt {b} x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{b^2} \\ & = \frac {2 (A b-a B) \sqrt {x}}{b^2}+\frac {2 B x^{5/2}}{5 b}-\frac {\left (\sqrt {a} (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {x}\right )}{2 b^{5/2}}-\frac {\left (\sqrt {a} (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {x}\right )}{2 b^{5/2}}+\frac {\left (\sqrt [4]{a} (A b-a B)\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {x}\right )}{2 \sqrt {2} b^{9/4}}+\frac {\left (\sqrt [4]{a} (A b-a B)\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {x}\right )}{2 \sqrt {2} b^{9/4}} \\ & = \frac {2 (A b-a B) \sqrt {x}}{b^2}+\frac {2 B x^{5/2}}{5 b}+\frac {\sqrt [4]{a} (A b-a B) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{9/4}}-\frac {\sqrt [4]{a} (A b-a B) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{9/4}}-\frac {\left (\sqrt [4]{a} (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{9/4}}+\frac {\left (\sqrt [4]{a} (A b-a B)\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{9/4}} \\ & = \frac {2 (A b-a B) \sqrt {x}}{b^2}+\frac {2 B x^{5/2}}{5 b}+\frac {\sqrt [4]{a} (A b-a B) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{9/4}}-\frac {\sqrt [4]{a} (A b-a B) \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{\sqrt {2} b^{9/4}}+\frac {\sqrt [4]{a} (A b-a B) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{9/4}}-\frac {\sqrt [4]{a} (A b-a B) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{2 \sqrt {2} b^{9/4}} \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 150, normalized size of antiderivative = 0.59 \[ \int \frac {x^{3/2} \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {2 \sqrt {x} \left (5 A b-5 a B+b B x^2\right )}{5 b^2}-\frac {\sqrt [4]{a} (-A b+a B) \arctan \left (\frac {\sqrt {a}-\sqrt {b} x}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}\right )}{\sqrt {2} b^{9/4}}+\frac {\sqrt [4]{a} (-A b+a B) \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}{\sqrt {a}+\sqrt {b} x}\right )}{\sqrt {2} b^{9/4}} \]
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Time = 2.77 (sec) , antiderivative size = 138, normalized size of antiderivative = 0.54
method | result | size |
risch | \(\frac {2 \left (b B \,x^{2}+5 A b -5 B a \right ) \sqrt {x}}{5 b^{2}}-\frac {\left (A b -B a \right ) \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{4 b^{2}}\) | \(138\) |
derivativedivides | \(\frac {\frac {2 b B \,x^{\frac {5}{2}}}{5}+2 A b \sqrt {x}-2 B a \sqrt {x}}{b^{2}}-\frac {\left (A b -B a \right ) \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{4 b^{2}}\) | \(141\) |
default | \(\frac {\frac {2 b B \,x^{\frac {5}{2}}}{5}+2 A b \sqrt {x}-2 B a \sqrt {x}}{b^{2}}-\frac {\left (A b -B a \right ) \left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {x +\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}{x -\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {x}\, \sqrt {2}+\sqrt {\frac {a}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{4 b^{2}}\) | \(141\) |
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Result contains complex when optimal does not.
Time = 0.27 (sec) , antiderivative size = 597, normalized size of antiderivative = 2.34 \[ \int \frac {x^{3/2} \left (A+B x^2\right )}{a+b x^2} \, dx=-\frac {5 \, b^{2} \left (-\frac {B^{4} a^{5} - 4 \, A B^{3} a^{4} b + 6 \, A^{2} B^{2} a^{3} b^{2} - 4 \, A^{3} B a^{2} b^{3} + A^{4} a b^{4}}{b^{9}}\right )^{\frac {1}{4}} \log \left (b^{2} \left (-\frac {B^{4} a^{5} - 4 \, A B^{3} a^{4} b + 6 \, A^{2} B^{2} a^{3} b^{2} - 4 \, A^{3} B a^{2} b^{3} + A^{4} a b^{4}}{b^{9}}\right )^{\frac {1}{4}} - {\left (B a - A b\right )} \sqrt {x}\right ) + 5 i \, b^{2} \left (-\frac {B^{4} a^{5} - 4 \, A B^{3} a^{4} b + 6 \, A^{2} B^{2} a^{3} b^{2} - 4 \, A^{3} B a^{2} b^{3} + A^{4} a b^{4}}{b^{9}}\right )^{\frac {1}{4}} \log \left (i \, b^{2} \left (-\frac {B^{4} a^{5} - 4 \, A B^{3} a^{4} b + 6 \, A^{2} B^{2} a^{3} b^{2} - 4 \, A^{3} B a^{2} b^{3} + A^{4} a b^{4}}{b^{9}}\right )^{\frac {1}{4}} - {\left (B a - A b\right )} \sqrt {x}\right ) - 5 i \, b^{2} \left (-\frac {B^{4} a^{5} - 4 \, A B^{3} a^{4} b + 6 \, A^{2} B^{2} a^{3} b^{2} - 4 \, A^{3} B a^{2} b^{3} + A^{4} a b^{4}}{b^{9}}\right )^{\frac {1}{4}} \log \left (-i \, b^{2} \left (-\frac {B^{4} a^{5} - 4 \, A B^{3} a^{4} b + 6 \, A^{2} B^{2} a^{3} b^{2} - 4 \, A^{3} B a^{2} b^{3} + A^{4} a b^{4}}{b^{9}}\right )^{\frac {1}{4}} - {\left (B a - A b\right )} \sqrt {x}\right ) - 5 \, b^{2} \left (-\frac {B^{4} a^{5} - 4 \, A B^{3} a^{4} b + 6 \, A^{2} B^{2} a^{3} b^{2} - 4 \, A^{3} B a^{2} b^{3} + A^{4} a b^{4}}{b^{9}}\right )^{\frac {1}{4}} \log \left (-b^{2} \left (-\frac {B^{4} a^{5} - 4 \, A B^{3} a^{4} b + 6 \, A^{2} B^{2} a^{3} b^{2} - 4 \, A^{3} B a^{2} b^{3} + A^{4} a b^{4}}{b^{9}}\right )^{\frac {1}{4}} - {\left (B a - A b\right )} \sqrt {x}\right ) - 4 \, {\left (B b x^{2} - 5 \, B a + 5 \, A b\right )} \sqrt {x}}{10 \, b^{2}} \]
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Time = 4.74 (sec) , antiderivative size = 275, normalized size of antiderivative = 1.08 \[ \int \frac {x^{3/2} \left (A+B x^2\right )}{a+b x^2} \, dx=\begin {cases} \tilde {\infty } \left (2 A \sqrt {x} + \frac {2 B x^{\frac {5}{2}}}{5}\right ) & \text {for}\: a = 0 \wedge b = 0 \\\frac {\frac {2 A x^{\frac {5}{2}}}{5} + \frac {2 B x^{\frac {9}{2}}}{9}}{a} & \text {for}\: b = 0 \\\frac {2 A \sqrt {x} + \frac {2 B x^{\frac {5}{2}}}{5}}{b} & \text {for}\: a = 0 \\\frac {2 A \sqrt {x}}{b} + \frac {A \sqrt [4]{- \frac {a}{b}} \log {\left (\sqrt {x} - \sqrt [4]{- \frac {a}{b}} \right )}}{2 b} - \frac {A \sqrt [4]{- \frac {a}{b}} \log {\left (\sqrt {x} + \sqrt [4]{- \frac {a}{b}} \right )}}{2 b} - \frac {A \sqrt [4]{- \frac {a}{b}} \operatorname {atan}{\left (\frac {\sqrt {x}}{\sqrt [4]{- \frac {a}{b}}} \right )}}{b} - \frac {2 B a \sqrt {x}}{b^{2}} - \frac {B a \sqrt [4]{- \frac {a}{b}} \log {\left (\sqrt {x} - \sqrt [4]{- \frac {a}{b}} \right )}}{2 b^{2}} + \frac {B a \sqrt [4]{- \frac {a}{b}} \log {\left (\sqrt {x} + \sqrt [4]{- \frac {a}{b}} \right )}}{2 b^{2}} + \frac {B a \sqrt [4]{- \frac {a}{b}} \operatorname {atan}{\left (\frac {\sqrt {x}}{\sqrt [4]{- \frac {a}{b}}} \right )}}{b^{2}} + \frac {2 B x^{\frac {5}{2}}}{5 b} & \text {otherwise} \end {cases} \]
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Time = 0.28 (sec) , antiderivative size = 235, normalized size of antiderivative = 0.92 \[ \int \frac {x^{3/2} \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {{\left (\frac {2 \, \sqrt {2} {\left (B a - A b\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {b} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {b}}} + \frac {2 \, \sqrt {2} {\left (B a - A b\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {b} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {b}}} + \frac {\sqrt {2} {\left (B a - A b\right )} \log \left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} \sqrt {x} + \sqrt {b} x + \sqrt {a}\right )}{a^{\frac {3}{4}} b^{\frac {1}{4}}} - \frac {\sqrt {2} {\left (B a - A b\right )} \log \left (-\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} \sqrt {x} + \sqrt {b} x + \sqrt {a}\right )}{a^{\frac {3}{4}} b^{\frac {1}{4}}}\right )} a}{4 \, b^{2}} + \frac {2 \, {\left (B b x^{\frac {5}{2}} - 5 \, {\left (B a - A b\right )} \sqrt {x}\right )}}{5 \, b^{2}} \]
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Time = 0.28 (sec) , antiderivative size = 263, normalized size of antiderivative = 1.03 \[ \int \frac {x^{3/2} \left (A+B x^2\right )}{a+b x^2} \, dx=\frac {\sqrt {2} {\left (\left (a b^{3}\right )^{\frac {1}{4}} B a - \left (a b^{3}\right )^{\frac {1}{4}} A b\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{2 \, b^{3}} + \frac {\sqrt {2} {\left (\left (a b^{3}\right )^{\frac {1}{4}} B a - \left (a b^{3}\right )^{\frac {1}{4}} A b\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{2 \, b^{3}} + \frac {\sqrt {2} {\left (\left (a b^{3}\right )^{\frac {1}{4}} B a - \left (a b^{3}\right )^{\frac {1}{4}} A b\right )} \log \left (\sqrt {2} \sqrt {x} \left (\frac {a}{b}\right )^{\frac {1}{4}} + x + \sqrt {\frac {a}{b}}\right )}{4 \, b^{3}} - \frac {\sqrt {2} {\left (\left (a b^{3}\right )^{\frac {1}{4}} B a - \left (a b^{3}\right )^{\frac {1}{4}} A b\right )} \log \left (-\sqrt {2} \sqrt {x} \left (\frac {a}{b}\right )^{\frac {1}{4}} + x + \sqrt {\frac {a}{b}}\right )}{4 \, b^{3}} + \frac {2 \, {\left (B b^{4} x^{\frac {5}{2}} - 5 \, B a b^{3} \sqrt {x} + 5 \, A b^{4} \sqrt {x}\right )}}{5 \, b^{5}} \]
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Time = 5.16 (sec) , antiderivative size = 789, normalized size of antiderivative = 3.09 \[ \int \frac {x^{3/2} \left (A+B x^2\right )}{a+b x^2} \, dx=\sqrt {x}\,\left (\frac {2\,A}{b}-\frac {2\,B\,a}{b^2}\right )+\frac {2\,B\,x^{5/2}}{5\,b}-\frac {{\left (-a\right )}^{1/4}\,\mathrm {atan}\left (\frac {\frac {{\left (-a\right )}^{1/4}\,\left (A\,b-B\,a\right )\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^2\,b^2-2\,A\,B\,a^3\,b+B^2\,a^4\right )}{b}-\frac {{\left (-a\right )}^{1/4}\,\left (32\,A\,a^2\,b^2-32\,B\,a^3\,b\right )\,\left (A\,b-B\,a\right )}{2\,b^{9/4}}\right )\,1{}\mathrm {i}}{2\,b^{9/4}}+\frac {{\left (-a\right )}^{1/4}\,\left (A\,b-B\,a\right )\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^2\,b^2-2\,A\,B\,a^3\,b+B^2\,a^4\right )}{b}+\frac {{\left (-a\right )}^{1/4}\,\left (32\,A\,a^2\,b^2-32\,B\,a^3\,b\right )\,\left (A\,b-B\,a\right )}{2\,b^{9/4}}\right )\,1{}\mathrm {i}}{2\,b^{9/4}}}{\frac {{\left (-a\right )}^{1/4}\,\left (A\,b-B\,a\right )\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^2\,b^2-2\,A\,B\,a^3\,b+B^2\,a^4\right )}{b}-\frac {{\left (-a\right )}^{1/4}\,\left (32\,A\,a^2\,b^2-32\,B\,a^3\,b\right )\,\left (A\,b-B\,a\right )}{2\,b^{9/4}}\right )}{2\,b^{9/4}}-\frac {{\left (-a\right )}^{1/4}\,\left (A\,b-B\,a\right )\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^2\,b^2-2\,A\,B\,a^3\,b+B^2\,a^4\right )}{b}+\frac {{\left (-a\right )}^{1/4}\,\left (32\,A\,a^2\,b^2-32\,B\,a^3\,b\right )\,\left (A\,b-B\,a\right )}{2\,b^{9/4}}\right )}{2\,b^{9/4}}}\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{b^{9/4}}-\frac {{\left (-a\right )}^{1/4}\,\mathrm {atan}\left (\frac {\frac {{\left (-a\right )}^{1/4}\,\left (A\,b-B\,a\right )\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^2\,b^2-2\,A\,B\,a^3\,b+B^2\,a^4\right )}{b}-\frac {{\left (-a\right )}^{1/4}\,\left (32\,A\,a^2\,b^2-32\,B\,a^3\,b\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{2\,b^{9/4}}\right )}{2\,b^{9/4}}+\frac {{\left (-a\right )}^{1/4}\,\left (A\,b-B\,a\right )\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^2\,b^2-2\,A\,B\,a^3\,b+B^2\,a^4\right )}{b}+\frac {{\left (-a\right )}^{1/4}\,\left (32\,A\,a^2\,b^2-32\,B\,a^3\,b\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{2\,b^{9/4}}\right )}{2\,b^{9/4}}}{\frac {{\left (-a\right )}^{1/4}\,\left (A\,b-B\,a\right )\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^2\,b^2-2\,A\,B\,a^3\,b+B^2\,a^4\right )}{b}-\frac {{\left (-a\right )}^{1/4}\,\left (32\,A\,a^2\,b^2-32\,B\,a^3\,b\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{2\,b^{9/4}}\right )\,1{}\mathrm {i}}{2\,b^{9/4}}-\frac {{\left (-a\right )}^{1/4}\,\left (A\,b-B\,a\right )\,\left (\frac {16\,\sqrt {x}\,\left (A^2\,a^2\,b^2-2\,A\,B\,a^3\,b+B^2\,a^4\right )}{b}+\frac {{\left (-a\right )}^{1/4}\,\left (32\,A\,a^2\,b^2-32\,B\,a^3\,b\right )\,\left (A\,b-B\,a\right )\,1{}\mathrm {i}}{2\,b^{9/4}}\right )\,1{}\mathrm {i}}{2\,b^{9/4}}}\right )\,\left (A\,b-B\,a\right )}{b^{9/4}} \]
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